Freely Falling Objects
A free falling object is an object that is falling under the sole influence of gravity. Any object that is being acted upon only by the force of gravity is said to be in a state of free fall.
Free-falling objects do not encounter air resistance. All free-falling objects on earth accelerates downward at a rate of 9.80 m/s2
~ physicsclassroom.com~
Free fall is a kind of motion that everybody can observe in daily life. We drop something accidentally or purposely and see its motion. At the beginning it has a low speed and until the end it gains speed and before the crash it reaches its maximum speed.
~physicstutorials.org~
Kinematic Equations for Free Fall
1.) Vf = Vi - gt
2.) ∆ y = Vit -
gt 23.) Vf 2 = Vi2 - 2g ∆ y
4.) ∆ y =
( Vi+ Vf ) t
Problem Solving:
Examples:
1.) Luke Autbeloe drops a pile of roof shingles from the top of a roof located 8.52 meters above the ground. Determine the time required for the shingles to reach the ground.
Given:
Vi= 0 m/s
∆ y = -8.52 m
g = -9.8 m/s²
Find: t
Formula: ∆ y = Vit - (gt²)/2
Solution:
- 8.52 m = (0 m/s)(t) - (9.8 m/s²)(t²)/2
-8.52 m = (-4.9 m/s²)(t²)
(-8.52 m)/(-4.9 m/s²) = t²
1.739s² = t²
1.32 s = t
2.) Rex throws his mother's crystal vase vertically upwards with an initial velocity of 26.2 m/s. Determine the height to which the vase will rise above its initial height.
Given:
Vi = 26.2 m/s
Vf = 0 m/s
g = 9.8 m/s²
Find: ∆ y
Formula: Vf 2 = Vi2 - 2g ∆ y
Solution:
(0 m/s)² = (26.2 m/s)² - 2(9.8 m/s²)∆ y
0 m²/s² = 686.44m²/s² - 19.6 m/s² (
∆ y )
0 m²/s² -
686.44 m²/s² = - 19.6 m/s² ( ∆ y )
(-686.44 m²/s²)/(- 19.6 m/s² ) = ∆ y
35.0 = ∆ y
~physicsclassroom.com~
More Free Fall Problems here:) ( http://physics.defamilie.com/Kinematics/free%20fall%20sols.pdf )
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